BECE 2017 Mathematics Past Questions and Answers
The BECE 2017 Mathematics paper has 40 objective and 6 theory questions. Here are sample objective questions with the correct answers and explanations. Sit the full paper with the real time limit on ePrep.
Sample questions with answers
1. If Q = {1,3,5,7,9,10,11,13,15} and T = {1,2,3,5,6,7,10,11,12}, find Q ∪ T.
- A. {1,2,3,5,7,10,11}
- B. {1,3,5,7,9,11,13,15}
- C. {1,2,3,4,5,6,7,8,9,10,11,12,13}
- D. {1,2,3,5,6,7,9,10,11,12,13,15}
Answer: D. {1,2,3,5,6,7,9,10,11,12,13,15}
Union is obtained by listing each of the items (numbers) in the sets in ascending order without repeating any of the items (numbers)
Q = {1,3,5,7,9,10,11,13,15} and T = {1,2,3,5,6,7,10,11,12}
Q ∪ T = {1,2,3,5,6,7,9,10,11,12,13,15}
Union is obtained by listing each of the items (numbers) in the sets in ascending order without repeating any of the items (numbers)
Q = {1,3,5,7,9,10,11,13,15} and T = {1,2,3,5,6,7,10,11,12}
Q ∪ T = {1,2,3,5,6,7,9,10,11,12,13,15}
2. If 21:2*x* = 7:12, find the value of x.
- A. 10
- B. 12
- C. 15
- D. 18
Answer: D. 18
Change the ratios to fractions and solve for the value of x
Cross multiply and solve for x
2*x* x 7 = 21 x 12
Divide both sides of the equation by 2 x 7 to make x the subject since 2 x 7 will cancel each other
x = 3 x 6 = 18
Change the ratios to fractions and solve for the value of x
Cross multiply and solve for x
2*x* x 7 = 21 x 12
Divide both sides of the equation by 2 x 7 to make x the subject since 2 x 7 will cancel each other
x = 3 x 6 = 18
3. Given that
, find the value of p.
, find the value of p.
- A. 4
- B. 3
- C. 2
- D. 1
Answer: A. 4
Cross multiply and solve for p
2*p* x 1 = 1 x 8
Divide both sides of the equation by 2 x 1 to make p the subject since 2 x 1 will cancel each other
p = 4
Cross multiply and solve for p
2*p* x 1 = 1 x 8
Divide both sides of the equation by 2 x 1 to make p the subject since 2 x 1 will cancel each other
p = 4
4. Simplify 3*q* x 12*pq*.
- A. A. 15*pq*$^{2}$
- B. 15*p*$^{2}$q
- C. 36*pq*$^{2}$
- D. 36*p*$^{2}$q
Answer: C. 36*pq*$^{2}$
Applying the law of multiplication of indices
a$^{m}$ x a$^{n}$ = a$^{m+n}$
3*q* x 12*pq* = 3 x 12 x q$^{1}$ x q$^{1}$ x p
3*q* x 12*pq* = 3 x 12 x q$^{1+1}$ x p
3*q* x 12*pq* = 36*q*$^{2}$p = 36*p**q*$^{2}$
Applying the law of multiplication of indices
a$^{m}$ x a$^{n}$ = a$^{m+n}$
3*q* x 12*pq* = 3 x 12 x q$^{1}$ x q$^{1}$ x p
3*q* x 12*pq* = 3 x 12 x q$^{1+1}$ x p
3*q* x 12*pq* = 36*q*$^{2}$p = 36*p**q*$^{2}$
5. If A = {2,6,8} and B = {4,6,8,10}, which of the following statements is true?
- A. A ⊂ B
- B. A ∩ B = {2,6,8}
- C. A ∪ B = {2,4,6,8,10}
- D. A ⊃ B
Answer: C. A ∪ B = {2,4,6,8,10}
Union is obtained by listing each of the items (numbers) in the sets in ascending order without repeating any of the items (numbers)
Union is obtained by listing each of the items (numbers) in the sets in ascending order without repeating any of the items (numbers)
6. Find the product of 4*xy*$^{4}$ and x$^{2}$yz.
- A. 4*x*$^{3}$y$^{4}$z
- B. 4*x*$^{3}$y$^{5}$z
- C. 4*x*$^{2}$y$^{4}$z
- D. 4*x*$^{2}$y$^{4}$
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7. The sum of the interior angles of a regular polygon with 10 sides is
- A. 144$^{o}$.
- B. 900$^{o}$.
- C. 1,440$^{o}$.
- D. 1,800$^{o}$.
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8. Solve
.
.
- A.
- B.
- C.
- D.
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9. The ages of the members of a social club are 20 years, 55 years, 60 years and 25 years. Find the mean age of the members of the club.
- A. 20 years
- B. 30 years
- C. 40 years
- D. 50 years
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10. Evelyn saved GH₵ 35.48 every month for 8 months. How much did she save?
- A. GH₵ 183.60
- B. GH₵ 280.63
- C. GH₵ 283.20
- D. GH₵ 283.84
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