BECE 1991 Mathematics Past Questions and Answers
The BECE 1991 Mathematics paper has 40 objective and 4 theory questions. Here are sample objective questions with the correct answers and explanations. Sit the full paper with the real time limit on ePrep.
Sample questions with answers
1. P = {1, 2, 3, 8, 10}, Q = {8, 1, x, 3, 2}. If P = Q, what is the value of x?
- A. 1
- B. 2
- C. 3
- D. 8
- E. 10
Answer: E. 10
Equal sets are sets in which the number of elements is the same and all elements are equal.
Since P = Q, all the elements in P are found in Q. Hence the missing number 10 is x
Equal sets are sets in which the number of elements is the same and all elements are equal.
Since P = Q, all the elements in P are found in Q. Hence the missing number 10 is x
2. If Y = {house, tree} and V = {cat, house, tree} which of the following is true of Y and V?
- A. Y = V
- B. Y ⊂ V
- C. V ⊂ Y
- D. V ∈ Y
Answer: B. Y ⊂ V
If the set A is a subset (⊂) of B then all the elements of A are found in B.
Y ⊂ V because all the elements (house, tree) of A are found in the set V.
If the set A is a subset (⊂) of B then all the elements of A are found in B.
Y ⊂ V because all the elements (house, tree) of A are found in the set V.
3. The following addition is in base ten. Find the missing addend.
| | 2 | 3 | 4 | 5 |
|---|---|---|---|---|
| + | 1 | 0 | 4 | 5 |
| | * | * | * | * |
| | 5 | 1 | 1 | 0 |
| | 2 | 3 | 4 | 5 |
|---|---|---|---|---|
| + | 1 | 0 | 4 | 5 |
| | * | * | * | * |
| | 5 | 1 | 1 | 0 |
- A. 1300
- B. 1720
- C. 2765
- D. 4065
Answer: B. 1720
Let n = the missing addend.
2345 + 1045 + n = 5110
3390 + n = 5110
n = 5110 - 3390
n = 1720
Let n = the missing addend.
2345 + 1045 + n = 5110
3390 + n = 5110
n = 5110 - 3390
n = 1720
4. Given that 2$^{2}$ x 3$^{2}$ x 7 = 252, find the least number that should be multiplied by 252 to make the product a perfect square.
- A. 2
- B. 3
- C. 6
- D. 7
Answer: D. 7
A number expressed as a product of an integer by itself is called a perfect square. A perfect square is a special type of number that you get by multiplying another number by itself.
As you can see both 2 and 3 are being multiplied by the same number producing the power 2. If multiplied by 7, the 7 will also have a power of 2.
2$^{2}$ x 3$^{2}$ x 7 x 7 = 2$^{2}$ x 3$^{2}$ x 7$^{2}$
A number expressed as a product of an integer by itself is called a perfect square. A perfect square is a special type of number that you get by multiplying another number by itself.
As you can see both 2 and 3 are being multiplied by the same number producing the power 2. If multiplied by 7, the 7 will also have a power of 2.
2$^{2}$ x 3$^{2}$ x 7 x 7 = 2$^{2}$ x 3$^{2}$ x 7$^{2}$
5. Write 4687.02 in standard form.
- A. 46.8702 x 10$^{3}$
- B. 46.8702 x 10$^{4}$
- C. 4.68702 x 10$^{5}$
- D. 4.68702 x 10$^{3}$
Answer: D. 4.68702 x 10$^{3}$
A standard form should be in the form a.bcde x 10$^{n}$
The decimal point must be after the first non-zero digit.
The n is the number of times the decimal point has to be moved to be right after the first non-zero digit.
If it is moved to the left, the n is positive and if to the right, n is negative.
4687.02 = 4.⌒6⌒8⌒7.02 = 4.68702 x 10$^{3}$
A standard form should be in the form a.bcde x 10$^{n}$
The decimal point must be after the first non-zero digit.
The n is the number of times the decimal point has to be moved to be right after the first non-zero digit.
If it is moved to the left, the n is positive and if to the right, n is negative.
4687.02 = 4.⌒6⌒8⌒7.02 = 4.68702 x 10$^{3}$
6. Convert 11001$_{two}$ to a decimal numeral.
- A. 6
- B. 7
- C. 14
- D. 25
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7. A boy spent $\frac{2}{7}$ of his pocket money on transport and $\frac{1}{5}$ on sweets. What fraction of his pocket money does he spend on transport and sweets?
- A. $\frac{2}{35}$
- B. $\frac{3}{35}$
- C. $\frac{1}{7}$
- D. $\frac{17}{35}$
Answer and explanation: practise this paper on ePrep.
8. The product of three numbers is 1197. Two of the numbers are 3 and 19. Find the third number.
- A. 21
- B. 54
- C. 210
- D. 544
Answer and explanation: practise this paper on ePrep.
9. Find the GCF (HCF) of 2$^{3}$ × 3$^{2}$ and 2$^{3}$ × 3$^{4}$.
- A. 8
- B. 9
- C. 72
- D. 81
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10. Use the diagram below to answer the question below.
Find the value of a°
Find the value of a°
- A. 68°
- B. 75°
- C. 105°
- D. 112°
- E. 124°
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Answer all 44 questions of the BECE 1991 Mathematics paper
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