BECE 1990 Mathematics Past Questions and Answers
The BECE 1990 Mathematics paper has 39 objective and 4 theory questions. Here are sample objective questions with the correct answers and explanations. Sit the full paper with the real time limit on ePrep.
Sample questions with answers
1. If P = {7, 9, 13}, Q = {1, 7, 13}. Find P ∩ Q.
- A. {1, 7, 13}
- B. {1, 9, 13}
- C. {7, 13}
- D. {7, 9, 13}
Answer: C. {7, 13}
Intersection (∩) are elements that can be found in both sets
Intersection (∩) are elements that can be found in both sets
2. In the diagram, Q is the set of numbers inside the circle and T is the set of numbers inside the triangle. Find Q U T.
- A. {5}
- B. {6, 7}
- C. {3, 4, 5}
- D. {5, 6, 7}
- E. {3, 4, 5, 6, 7}
Answer: E. {3, 4, 5, 6, 7}
Union (∪) is simply listing each of the elements from both sets. If an element appeared in both sets, it is listed only once.
Union (∪) is simply listing each of the elements from both sets. If an element appeared in both sets, it is listed only once.
4. Convert 25$_{ten}$ to a base two numeral.
A
A
- A. 1000
- B. 100111
- C. 10101
- D. 11001
Answer: D. 11001
25 base 10 to base 2
$\begin{matrix} & 25 \\ 2 & 12 r 1 \\ 2 & 6 r 0 \\ 2 & 3 r 0 \\ 2 & 1 r 1 \\ 2 & 0 r 1\end{matrix}$
You list the remainders from the bottom to the top.
25$_{ten}$ = 11001$_{two}$
25 base 10 to base 2
$\begin{matrix} & 25 \\ 2 & 12 r 1 \\ 2 & 6 r 0 \\ 2 & 3 r 0 \\ 2 & 1 r 1 \\ 2 & 0 r 1\end{matrix}$
You list the remainders from the bottom to the top.
25$_{ten}$ = 11001$_{two}$
5. If (3.14 × 18) × 17.5 = 3.14 × (3*a* × 17.5). Find the value of a.
- A. 3.0
- B. 5.8
- C. 6.0
- D. 9.0
Answer: C. 6.0
(3.14 × 18) × 17.5 = 3.14 × (3*a* × 17.5)
3.14 × 18 × 17.5 = 3.14 × 3*a* × 17.5
The common numbers cancel each other.
18 = 3*a*
Divide both sides by 3
a = $\frac{18}{3}$ = 6
(3.14 × 18) × 17.5 = 3.14 × (3*a* × 17.5)
3.14 × 18 × 17.5 = 3.14 × 3*a* × 17.5
The common numbers cancel each other.
18 = 3*a*
Divide both sides by 3
a = $\frac{18}{3}$ = 6
6. If 26039 oranges are shared equally among 13 women, how many oranges does each woman receive?
- A. 23
- B. 1203
- C. 230
- D. 2003
Answer: D. 2003
Oranges received by each = $\frac{26039}{13}$ = 2003
Oranges received by each = $\frac{26039}{13}$ = 2003
7. Mr. Mensah withdrew some money from the bank. He gave $\frac{1}{2}$ of it to his sons and $\frac{1}{3}$ to his daughter. If he had ₵500.00 left, how much did he take from the bank?
- A. ₵600.00
- B. ₵750.00
- C. ₵1500.00
- D. ₵2000.00
- E. ₵3,000.00
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8. Simplify $\frac{1}{2}$(1$\frac{1}{2}$ + $\frac{3}{4}$ ÷ $\frac{1}{4}$ )
- A. 1$\frac{1}{2}$
- B. 2$\frac{1}{4}$
- C. 2$\frac{3}{4}$
- D. 4$\frac{1}{2}$
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9. If 21 : 2*x* = 7 : 10, find x.
- A. 3
- B. 2$\frac{1}{4}$
- C. 15
- D. 35
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10. X is a point on the line segment AB such that |AB| = 10 cm and |AX| = 4 cm.
Find the ratio |AX| : |XB|
Find the ratio |AX| : |XB|
- A. 5 : 3
- B. 3 : 2
- C. 5 : 4
- D. 1 : 1
- E. 2 : 3
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11. In an examination, 60% of the candidates passed. The number that passed was 240. How many candidates failed?
- A. 140
- B. 160
- C. 360
- D. 400
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